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21x^2-13x-26=0
a = 21; b = -13; c = -26;
Δ = b2-4ac
Δ = -132-4·21·(-26)
Δ = 2353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{2353}}{2*21}=\frac{13-\sqrt{2353}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{2353}}{2*21}=\frac{13+\sqrt{2353}}{42} $
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